Final answer:
ACDE; ZABC ZDBE
Step-by-step explanation:
In the given problem, it's initially stated that ∠ABC is congruent to ∠CAB. From this information, using the corresponding angles postulate or the angle addition postulate, we can deduce that ∠ADE is congruent to ∠DEC. Additionally, given that AC is congruent to CB, it implies that AD is congruent to DC due to the Isosceles Triangle Theorem.
Therefore, by combining these angle and side relationships, triangles ADE and DEC are congruent by the Angle-Side-Angle (ASA) postulate, proving ACDE. Regarding the missing step, ZABC and ZDBE are corresponding angles in congruent triangles ADE and DEC, respectively. This correspondence of angles in congruent triangles ensures the equality of these angles, validating the statement ZABC ZDBE.
Starting from the information that ∠ABC is congruent to ∠CAB, it implies that the angles ∠ADE and ∠DEC are congruent. This deduction is due to the angles being corresponding in the congruent triangles ADE and DEC. Furthermore, the given information AC = CB leads to AD = DC by the Isosceles Triangle Theorem.
By proving that two angles and a side in one triangle are congruent to two angles and the corresponding side in another triangle, we establish the congruence of triangles ADE and DEC using the ASA postulate. Thus, the proof concludes with the establishment of ACDE. As for the missing step, ZABC and ZDBE correspond as angles in congruent triangles ADE and DEC, respectively, ensuring their equality, confirming the relationship ZABC ZDBE.