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Two airplanes leave the same airport. One heads north, and the other heads east. After some time, the northbound airplane has traveled 12 miles. If the two airplanes are 20 miles apart, how far has the eastbound airplane traveled?

User Yingqi
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1 Answer

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The eastbound airplane has traveled 16 miles.

This can be determined using the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

In this case, the distance the northbound airplane has traveled (12 miles) is one side of the triangle, the distance the eastbound airplane has traveled is the other side, and the distance between the two airplanes (20 miles) is the hypotenuse.

So, we can set up the equation as:

(distance eastbound airplane)^2 + 12^2 = 20^2

Solving for the distance eastbound airplane, we get:

distance eastbound airplane = sqrt(20^2 - 12^2) = sqrt(256 - 144) = sqrt(112) = 16 miles

User Hod Caspi
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