Question

Pls help!! “write the following metals using Roman numeral notation. Then explain why the Roman numeral differs for these metals. •Cu1+ •CoCl2

Answer 1

The Roman numerals for Cu1+ and CoCl2 are copper(I) and cobalt(II) respectively, indicating that copper has a +1 charge and cobalt has a +2 charge in these compounds. The Roman numeral notation is part of the Stock system, used for transition metals with variable charges to specify their exact positive charge.

Step-by-step explanation:

You've asked to write the Roman numeral notation for the metals in Cu1+ and CoCl2 and explain why the numeral differs for these metals. In ionic compounds, metals can have different charges, so Roman numerals are used to indicate the specific charge of the metal in a given compound. For example, Cu1+ is copper(I) as the Roman numeral I indicates that copper has a +1 charge. In the case of CoCl2, cobalt typically forms two kinds of ions, Co2+ and Co3+, but based on the formula CoCl2, we know that cobalt must have a +2 charge because two chloride ions (Cl-) would balance out the +2 charge to make the neutral compound cobalt(II) chloride. Therefore, we write cobalt as cobalt(II) in this context.

This system is known as the Stock system, used for transition metals which can form cations with variable charges. The Roman numeral in the name of a transition metal ion indicates the exact positive charge of that ion, and it helps us write the correct formula for ionic compounds and avoid ambiguity in compound names.

Answer 2

Cu1+ can be written as "Cu+" in Roman numeral notation.

CoCl2 can be written as "CoCl2" in Roman numeral notation.

Roman numeral notation is used to indicate the oxidation state of an element in a compound. The oxidation state is the charge an atom would have if all of the bonding electrons were assigned to the more electronegative atom. The + sign shows that Copper has lost an electron and now has a positive charge.

In the case of CoCl2, the Roman numeral notation is not used since cobalt does not have variable oxidation states and therefor it does not have any change in its charge to indicate.