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The value of the electric field at a distance of 28.8 m from a point charge is 68.3 N/C and is directed radially in toward the charge.

What is the charge? The Coulomb constant
is 8.98755 × 10⁹ Nm²/C².
Answer in units of C. Answer in units of
C.

User Evadne Wu
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8.3k points

1 Answer

2 votes

To determine the charge, we can use the equation for the electric field due to a point charge:

E = k * q / r^2

Where E is the electric field, k is the Coulomb constant (8.98755 x 10^9 Nm^2/C^2), q is the charge, and r is the distance from the point charge.

We can rearrange this equation to solve for q:

q = E * r^2 / k

Plugging in the given values:

q = (68.3 N/C) * (28.8 m)^2 / (8.98755 x 10^9 Nm^2/C^2)

q = (68.3 N/C) * (826.24 m^2) / (8.98755 x 10^9 Nm^2/C^2)

q = (68.3 N/C) * (826.24 m^2/C^2)

q = (68.3 N/C) * (826.24 / 8.98755 x 10^9) C

q = (68.3 N/C) * (9.26 x 10^-9) C

q = 6.36 x 10^-7 C

The charge is approximately 6.36 x 10^-7 Coulombs.

User Dan Head
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7.2k points