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The admission fee at an amusement park is $1.25 for children and $7.20 for adults. On a certain day, 253 people entered the park, and the admission fees collected totaled $1060. How many children and how many adults were admitted?

There were _______ children admitted.
There were _______ adults admitted

User Manquer
by
8.6k points

2 Answers

3 votes

Answer:

128 children, 128 adults

Explanation:

1.25 per child (c)

7.2 per adult (a)

a+c = 253 so c = 253-a

1.25c+7.2a=1060

2 equations 2 variables, solve

1.25 (253-a) + 7.2*a = 1.25*253 -1.25a + 7.2a =1060

sp 5.95a =1060- 1.25*253

so a =125

c = 253-125 = 128

User Andrew Lam
by
7.3k points
3 votes

This is a system of equations problem. We can set up the following equations:

x = number of children admitted

y = number of adults admitted

1.25x + 7.20y = 1060 (the total amount of money collected)

x + y = 253 (the total number of people admitted)

To find the number of children admitted, we can use the second equation to solve for one of the variables in terms of the other.

x + y = 253

x = 253 - y

Now we can substitute this expression into the first equation:

1.25(253 - y) + 7.20y = 1060

Solving for y we get

y = 120

So there were 120 adults admitted.

We can use the second equation to find the number of children admitted:

x + y = 253

x = 253 - y

x = 253 - 120

x = 133

So there were 133 children admitted.

Therefore,

There were 133 children admitted.

There were 120 adults admitted.

User Zymud
by
8.0k points