Question

Question 1: How many molecules are there in 67g of CO2?

Question2: What is the mass of 3.01 x 1023 atoms of FeO? Round to two decimal places.

Question3: If a sample contained 9.65 x 1023 atoms of iodine, how many grams would this be? Round to one decimal point.

Answer 1

1. The number of molecules in 67g of CO2 can be calculated using the molar mass of CO2, which is 44.01 g/mol. To find the number of molecules, we divide the mass of CO2 (67g) by the molar mass of CO2 (44.01 g/mol). This gives us: 67g / 44.01 g/mol = 1.52 x 10^23 molecules of CO2.

2. The mass of 3.01 x 10^23 atoms of FeO can be calculated using the molar mass of FeO, which is 71.847 g/mol. To find the mass, we multiply the number of atoms (3.01 x 10^23) by the molar mass of FeO (71.847 g/mol). This gives us: 3.01 x 10^23 atoms * 71.847 g/mol = 217.31 g

3. To calculate the mass of 9.65 x 10^23 atoms of iodine, we can use the molar mass of iodine, which is 126.904 g/mol. To find the mass, we multiply the number of atoms (9.65 x 10^23) by the molar mass of iodine (126.904 g/mol). This gives us: 9.65 x 10^23 atoms * 126.904 g/mol = 1218.56 g rounded to one decimal point.