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The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room. Which equations can be used to solve for y, the length of the room? Select three options. y(y + 5) = 750 y2 – 5y = 750 750 – y(y – 5) = 0 y(y – 5) + 750 = 0 (y + 25)(y – 30) = 0

User Djpeinado
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Answer:Option B , C and E are correct

Explanation:

y^2-5y=750

750-y(y-5)=0

(y+25)(y-30)=0

User Asad Awadia
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