Question

A manager bought lunch for her coworkers. Each person picked either a salad or a burger. The salads cost $8 each and the burgers cost $4 each. If the manager spent $152 and bought lunch for 28 people, how many of each item did she buy?

Answer 1

10, 8

Explanation:

Let x be the number of salads and y be the number of burgers.

We know that:

x + y = 28 (the total number of people)

8x + 4y = 152 (the total cost in dollars)

We can use the first equation to solve for one variable in terms of the other.

x = 28 - y

Now we can substitute this expression into the second equation:

8(28 - y) + 4y = 152

224 - 8y + 4y = 152

224 = 12y

y = 18 (burgers)

We can then use this value to find the number of salads

x = 28 - y = 28 - 18 = 10 (salads)

So the manager bought 10 salads and 18 burgers