Question

The initial and final velocities of a particle are shown in the figure below. Find the particle's average acceleration if the change in velocity takes place in a 11.5 s interval. (Let vi = 29.0 m/s and vf = 18.0 m/s.)

Answer 1

To calculate the average acceleration of the particle, we use the formula a = (vf - vi)/t, where vf is the final velocity, vi is the initial velocity, and t is the time interval. In this case, a = (18.0 m/s - 29.0 m/s)/11.5 s = -2.3 m/s2. Therefore, the average acceleration of the particle is -2.3 m/s2.