Question

Exercise 1: ABC is a triangle such that AB=5cm. A=50°and AC=5cm 1) Construct the triangle ABC. 2) What is the nature of the triangle ABC? Justity. 3) Calculate ABC and ACB. 4) Draw the height [AH) issued from A to [BC]. 5) a. Calculate BAH and CAH. b. What does [AH] represents for BAC? Justify.​

Answer 1

2) Acute triangle, isosceles

3) Both are 65 degrees

4) (diagram)

5) a) both 25 degrees

b) midpoint

Explanation:

2) If you're struggling search up "draw a triangle" and you'll find a website that will draw it for you. It will help you get an idea of it looks like and its nature.

3) We know that sides AB and AC are 5cm. So this triangle is an isosceles which makes the 2 remaining angles equal (if you draw a diagram it will be clear)

So:

180-50/2 = 65

ABC and ACB = 65 degrees each

4) Construct the line AH down the middle like in the diagram I drew.

5) a) Since AH is a straight line, we know that the angle AHB will be 90 degrees. After question 3 we also know that angle ABH is 65 degrees.

BAH = 180-90-65

BAH = 25 degrees

CAH = 50 - 25

CAH = 25 degrees

b) AH is the midpoint for BAC because the 2 segments formed are both 25 degrees.