Answer: The equation of a line can be written in the slope-intercept form y = mx + b, where m is the slope of the line and b is the y-intercept.
To find the equation of a line that passes through the point (3, 2) and cuts off equal intercepts on the x and y axes, we can use the following steps:
First, we need to find the slope of the line using the point (3, 2) and the fact that the line cuts off equal intercepts on the x and y axes. Since the line cuts off equal intercepts on the x and y axes, it means that it is a line of symmetry, which means that the slope of the line is zero.
Now we can use the point-slope form of a linear equation which is y-y1 = m(x-x1) and substitute the point (3,2) and the slope (0)
The equation of the line will be y = b where b is the y-intercept.
So the equation of the line which passes through the point (3, 2) and cuts off equal intercepts on the axes is y = 2
The line is a horizontal line passing through the point (3,2) and it cuts the x-axis at y = 2.
Explanation: