Question

2(3b+6) = 78
Algebra

Answer 1

2(3b+6) = 78

6b+ 12 = 78

Subtract 12 from both sides

6b+ 12 = 78

6b+12-12=78-12

6b = 66

b = 11

Answer 2

b = 11

Explanation:

2(3b + 6) = 78 (divide both sides by 2 )

3b + 6 = 39 ( subtract 6 from both sides )

3b = 33 ( divide both sides by 3 )

b = 11