Answer:
(3m−4)(9m2+12m+16)
Explanation:
this is difference of cubes (3m)^3 - (4)^3
now, apply difference of cubes formula
a^3−b^3 = (a−b)(a2+ab+b2)
where a=3m and b=4
(3m−4) ( (3)^2×(m)^2 + 4×3m + (4)^2)
(simplify)
27m^3-64 = (3m)^3 - (4)^3
= (3m-4)((3m)^2 + (3m)(4) + (4)^2)
= (3m-4)(9m^2 + 12m + 16)
The factored form of 27m^3-64 is (3m-4)(9m^2 + 12m + 16)
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