Question

What is the equation of the line that passes through the point (-6,-6) and has a slope of 5/3?

Answer 1

Answer: y=(5/3)x+4

Explanation:

m=5/3 (-6,-6)

A line in point-slope form is expressed as:

`y-y_1=m(x-x_1)\ \ \ \ \ (1)\\\\m=5/3\ \ \ \ x_1=-6 \ \ \ \ y_1=-6\\\\`

Substitute these values into equation (1):

`\displaystyle\\y-(-6)=(5)/(3)(x-(-6)) \\\\y+6=(5)/(3)(x+6) \\\\y+6=(5)/(3)(x)+(5)/(3) (6)\\\\y+6=(5)/(3)x+(5(2)(3))/(3) \\\\y+6=(5)/(3) x+5(2)\\\\y+6=(5)/(3) x+10\\\\y+6-6=(5)/(3) x+10-6\\\\y=(5)/(3)x+4`