Question

The sum of three consecutive numbers is 405. What is the
3rd numbers

Answer 1

136

Explanation:

Let the three consecutive numbers be a, a + 1, a + 2

Therefore,

a + a + 1 + a + 2 = 405

3a + 3 = 405

3a = 405 - 3

3a = 402

a = 402/3

a = 134

Third number = a + 2 = 134 + 2 = 136