Question

What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?

Quadratic formula: x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction

x = StartFraction 5 plus or minus 10 StartRoot 5 EndRoot Over 2 EndFraction
x = StartFraction negative 5 plus or minus 10 StartRoot 5 EndRoot Over 2 EndFraction
x = StartFraction negative 5 plus or minus StartRoot 5 EndRoot Over 2 EndFraction
x = StartFraction 5 plus or minus StartRoot 5 EndRoot Over 2 EndFraction]

Answer 1

Answer: The zeros of the function f(x) = x^2 + 5x + 5 are given by the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

In this case, a = 1, b = 5, and c = 5. Plugging these values into the formula, we get:

x = (-5 ± √(5^2 - 4(1)(5)))/2(1)

x = (-5 ± √(25 - 20))/2

x = (-5 ± √(5))/2

x = (-5 ± √5)/2

The zeros of the function are:

x = (-5 + √5)/2 and x = (-5 - √5)/2

in simplest radical form

x = (-5 + √5)/2 and x = (-5 - √5)/2

Explanation: