Question

a 2.0 kg ball is thrown at 2 m/s strikes a 20.0 kg person sitting at rest on a bench. the ball gets stuck in the person's hair. what is the velocity of the person and the ball?

Answer 1

0.18 m/s

Step-by-step explanation:

Conservation of Momentum Law: total P before the collision must equal total momentum after the collision. P = mv

(2.0 kg)(2 m/s) + (20.0 kg)(0 m/s) = (2.0 kg + 20 kg)v

before after

4 kg·m/s = (22.0 kg)v

v = (4 kg·m/s) / (22.0 kg) = 0.18 m/s