Question

Determine the exact value of 0 in the following equation if 0 < a < 27.--4cos 0 + 7 = -2V3+7

Answer 1

Given:

The trigonometric equation is,

`-4\cos \theta+7=-2\sqrt[]{3}+7`

Step-by-step explanation:

Simplify the equation for angle theta.

`\begin{gathered} -4\cos \theta+7=-2\sqrt[]{3}+7 \\ -4\cos \theta=-2\sqrt[]{3} \\ \cos \theta=\frac{-2\sqrt[]{3}}{-4} \\ \theta=\cos ^(-1)(\frac{\sqrt[]{3}}{2}) \\ =(\pi)/(6),(11\pi)/(6) \end{gathered}`

So answer is,