Answer: To solve these simultaneous equations, we can substitute one equation into the other.
4x-3 = 3x + y.
3x+y =2y+5x-12
If we substitute the first equation into the second equation, we get:
3(4x-3) + y = 2y+5x-12
12x -9 + y = 2y+5x-12
Now we can solve the system of equations by isolating one of the variables and then substituting it back in one of the equations.
12x - 9 + y = 2y + 5x - 12
y = -9 + 2y + 5x -12
y = 2y + 5x -21
y - 2y = 5x -21 -9
-y = 5x -30
y = -5x + 30
Now we can substitute the value of y back into one of the original equations, we have:
4x-3 = 3x + (-5x + 30)
4x-3 = -2x + 30
4x-3+2x = 30
6x -3 = 30
6x = 33
x = 5.5
Now we can substitute the value of x back into one of the original equations to find the value of y:
4x -3 = 3x + y
4(5.5) -3 = 3(5.5) + y
22 - 3 = 16.5 + y
19 = 16.5 + y
y = 2.5
So the solution to the system of equations is x = 5.5 and y = 2.5.
Explanation: