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4x-3 =3x + y. 3x+y =2y+5x-12
simultaneous equation
pls help​

User Hyarus
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1 Answer

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Answer: To solve these simultaneous equations, we can substitute one equation into the other.

4x-3 = 3x + y.

3x+y =2y+5x-12

If we substitute the first equation into the second equation, we get:

3(4x-3) + y = 2y+5x-12

12x -9 + y = 2y+5x-12

Now we can solve the system of equations by isolating one of the variables and then substituting it back in one of the equations.

12x - 9 + y = 2y + 5x - 12

y = -9 + 2y + 5x -12

y = 2y + 5x -21

y - 2y = 5x -21 -9

-y = 5x -30

y = -5x + 30

Now we can substitute the value of y back into one of the original equations, we have:

4x-3 = 3x + (-5x + 30)

4x-3 = -2x + 30

4x-3+2x = 30

6x -3 = 30

6x = 33

x = 5.5

Now we can substitute the value of x back into one of the original equations to find the value of y:

4x -3 = 3x + y

4(5.5) -3 = 3(5.5) + y

22 - 3 = 16.5 + y

19 = 16.5 + y

y = 2.5

So the solution to the system of equations is x = 5.5 and y = 2.5.

Explanation:

User Vedant Terkar
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