85.6k views
2 votes
Please help 100 points wrong answers and links will be reported

Circle and Show!
(4 points each: 1 for the correct answer and 3 for supporting work!)
For numbers 8 -12, check the box next to the correct answer and type your work for that
problem.
Work must support your answer selection for credit!

Please help 100 points wrong answers and links will be reported Circle and Show! (4 points-example-1
Please help 100 points wrong answers and links will be reported Circle and Show! (4 points-example-1
Please help 100 points wrong answers and links will be reported Circle and Show! (4 points-example-2
User Hatice
by
7.1k points

2 Answers

5 votes

Please find attached herewith the solutions of your questions.

Hope it helps.

If you have any query, feel free to ask.

Please help 100 points wrong answers and links will be reported Circle and Show! (4 points-example-1
Please help 100 points wrong answers and links will be reported Circle and Show! (4 points-example-2
User Zvez
by
8.0k points
3 votes

Answer:


\textsf{8.} \quad \textsf{B.}\;8x^3y


\textsf{9.} \quad \textsf{D.}\;81x^8


\textsf{10.} \quad \textsf{A.}\;10t^(-7)


\textsf{11.} \quad \textsf{C.}\;(3m^2)/(x^3)


\textsf{12.} \quad \textsf{B.}\;(1)/(3m^9)

Explanation:

Exponent Rules


\textsf{Product rule}: \quad a^b \cdot a^c=a^(b+c)


\textsf{Power rule}: \quad (a^b)^c=a^(bc)


\textsf{Quotient rule} \quad (a^b)/(a^c)=a^(b-c)


\textsf{Power of a Product rule}: \quad (ab)^c=a^(c) \cdot b^c


\textsf{Negative exponent rule} \quad a^(-n)=(1)/(a^n)

Question 8


\begin{aligned}\left(2x^2y^3\right)\left(4xy^(-2)\right)&=2 \cdot 4 \cdot x^2 \cdot x \cdot y^3 \cdot y^(-2)\\&=8\cdot x^((2+1))\cdot y^((3-2))\\&=8 \cdot x^3 \cdot y^1\\&=8x^3y\end{aligned}

Question 9


\begin{aligned}\left(3x^2\right)^4&=3^4 \cdot (x^2)^4\\&=81 \cdot x^((2 \cdot 4))\\&=81x^8\end{aligned}

Question 10


\begin{aligned}5t^(-2) \cdot 2t^(-5)&=5 \cdot 2 \cdot t^(-2) \cdot t^(-5)\\&=10 \cdot t^((-2-5))\\&=10t^(-7)\end{aligned}

Question 11


\begin{aligned}(6m^(10)x^4)/(2m^8x^7)&=(6)/(2) \cdot (m^(10))/(m^8) \cdot (x^4)/(x^7)\\\\&=3 \cdot m^((10-8)) \cdot x^((4-7))\\\\&=3m^2x^(-3)\\\\&=(3m^2)/(x^3)\end{aligned}

Question 12


\begin{aligned}(m^(-3))/(3m^6)&=(1)/(3) \cdot (m^(-3))/(m^(6))\\\\&=(1)/(3) \cdot m^((-3-6))\\\\&=(1)/(3) \cdot m^(-9)\\\\&=(1)/(3m^9)\end{aligned}

User Nate Schreiner
by
7.8k points