Question

The age of a father is three times that of his son, but six years ago, the sum of their ages was 45. What is the present age of the son?

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Answer 1

Answer: Let's call the present age of the son x and the present age of the father y.

We know that y = 3x and that six years ago, the sum of their ages was 45.

So, we can write the equation:

x + (y-6) = 45

x + (3x-6) = 45

4x = 51

x = 12.75

The present age of the son is 12.75 years.

Explanation: