Answer:
A) solution 2 is more acidic than solution 1
Explanation:
A chemist prepares two acid solutions:
Solution 1: 3 parts sulfuric acid to 7 parts water
Ratio of sulphur to water: 3/7 (3:7)
Solution 2: 4 parts sulfuric acid to 9 parts water
Ratio of sulphur to water: 4/9 (4:9)
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Part A: (using ratios to determine which solution is more acidic)
First we make same denominator, since the denominators are 9 and 7, we have to find the lcm (lowest common multiple) they both have with is 63. To do that, we must multiply the denominators with either 7 or 9.
Solution 1: Numerator (3) multiplied by 9 and then denominator (7) multiplied by 9. This makes out fraction/ratio 27/63
Solution 2: Numerator (4) multiplied by 7 and then denominator (9) multiplied by 7. This makes out fraction/ratio 28/63
Since 28/63 (or just 28) is a larger quantity than 27/63 (or just 27) this means solution 2 is more acidic than solution 1.
Mathematical Line (Not sure what you would call this lol): 28 > 27
Part B: (Let 'y' amount of sulfuric acid mix with 'x' amount of water)
Equation of solution 1: y = 3/7x
Equation of solution 2: y = 4/9x
Please find attachment for graph.
Part C: Don't have a graph, sorry! (part a. method is more preferred to find more acidic because it gives the actual acidic amount.)