Question

What is the equation of a circle with a center (−8, 3) and radius of 8?

HELP!!!!!

(x − 8)2 + (y + 3)2 = 8

(x + 8)2 + (y − 3)2 = 8

(x − 8)2 + (y + 3)2 = 64

(x + 8)2 + (y − 3)2 = 64

Answer 1

(x + 8)^2 + (y - 3)^2 = 64

Explanation:

The equation of a circle with a center of (-8,3) and radius of 8 is:

(x + 8)^2 + (y - 3)^2 = 64

You can see that the center of the circle is represented by the point (-8,3) in the equation, and the radius is represented by the value on the right side of the equation (64) which is derived from 8^2