Question

Need help with math

Answer 1

to get the slope of any straight line, we simply need two points off of it, let's use those two in the picture below, keeping in mind that the y-intersect is when the graph intersects the y-axis, so

`(\stackrel{x_1}{-4}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{-1}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-1}-\stackrel{y1}{4}}}{\underset{\textit{\large run}} {\underset{x_2}{0}-\underset{x_1}{(-4)}}} \implies \cfrac{-5}{0 +4} \implies \cfrac{ -5 }{ 4 } \implies - \cfrac{5 }{ 4 } \\\\[-0.35em] ~\dotfill`

`\begin{array}ll \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \implies \qquad \begin{array}{llll} y=-\cfrac{5}{4}(~~x-(-1)~~) \\\\ {\Large \begin{array}{llll} y=-\cfrac{5}{4}(x+1) \end{array}} \end{array}`

Answer 2

Answer: C

Step-by-step explanation: The slope is -5/4 and the y intercept is -1