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Two identical charges, 2. 0 m apart, exert forces of magnitude 4. 0 n on each other. The value of either charge is:

User Ppilone
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1 Answer

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The value of either charge is 0.094 Coulombs.

The force between two charges is given by Coulomb's law, which states that the force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them. The equation is given by:

F = k * |q1*q2| / r^2

Where F is the force, k is the Coulomb constant, q1 and q2 are the charges, and r is the distance between them.

Given that the force between the two charges is 4.0 N and the distance between them is 2.0 m, we can rearrange the equation to solve for the charge:

q = sqrt(F * r^2 / k)

The Coulomb constant k is approximately 8.99 x 10^9 N*m^2/C^2.

Substituting the given values into the equation and solving for q, we get:

q = sqrt(4.0 N * (2.0 m)^2 / 8.99 x 10^9 N*m^2/C^2)

q = sqrt(0.0089) = 0.094 Coulombs.

So, the value of either charge is 0.094 Coulombs.

User Monk L
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