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Two families visit a museum. A family of two adults and four children pay £43.50. for entry. Another family of five adults and three children pay £65. for entry. Find, in pounds, the price of one adult ticket and one child ticket.

User Joshbrows
by
6.8k points

2 Answers

5 votes

Answer:

22.75

Explanation:

2a + 4c = 43.5

5a + 3c = 65

10a + 20c = 217.5

subtract

10a +6c = 130

= 14c = 87.5

c = 6.25

2a + 25 = 43.5

2a = 18.5

a = 16.5

16.5 + 6.25 = 22.75

User Qxn
by
7.0k points
1 vote

Answer:

One adult ticket costs £9.25, and one child ticket costs £6.25.

Explanation:

Let a = price of 1 adult ticket.

Let c = price of 1 child ticket.

"A family of two adults and four children pay £43.50. for entry."

2a + 4c = 43.5

"Another family of five adults and three children pay £65."

5a + 3c = 65

We have a system of simultaneous equation in two unknowns.

2a + 4c = 43.5

5a + 3c = 65

Let's solve the system by the method of elimination. We need to add multiples of the two equations in a way that one variable will be eliminated (add to zero).

Let's eliminate the variable a. Multiply both sides of the first equation by -5 Multiply both sides of the second equation by 2. Then add them.

-10a - 20c = -217.5

+ 10a + 6c = 130

----------------------------------

-14c = -87.5

c = 6.25

Now substitute 6.25 for c in the first original equation and solve for a.

2a + 4c = 43.5

2a + 4(6.25) = 43.5

2a + 25 = 43.5

2a = 18.5

a = 9.25

Answer: One adult ticket costs £9.25, and one child ticket costs £6.25.

User Ignacio Chiazzo
by
6.7k points