Answer:
A woman who is homozygous for the gene mutation that causes cystic fibrosis has a 25% chance of having a child with the disease if her partner does not carry the same mutation. This is because the mutation is recessive, so the child must inherit two copies of the mutated gene in order to display the trait. If the woman's partner does not carry the mutated gene, then the child only has a 25% chance of inheriting two copies of the mutated gene and thus displaying the trait.