Answer: 5 hardcover and 3 paperback
Step-by-step explanation: To solve, we need to keep this question in mind:
"How many books can we buy for each without going over the initiate amount [$26]?"
So, let's start with the $4 books, so knowing our multiples of 4
ex. 4, 8, 12, 16, 20, 24, 28......
So, I listed the example of the multiples. So, it can be either 20 or 24. So, it would be 20, because it is under the initiate amount AND it is less with unincluded paperback books. So, 26-20 = 6. So, if each paperback book costs $2, we need to divide 6 by 2. That's 3. So, therefore, she can buy 5 hardcovers and 3 paperbacks by spending all the money. I hope this helps!