Question

Quizz guyz •^•

What is the minimum length runway needed to accommodate airplanes that can accelerate uniformly at 2.7 m/s2 and must reach a ground velocity of 64 m/s before they can?

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Notes : Hi, I'm actually originally from Indonesia, sorry if my words are a bit lacking. Greetings from Indonesia guys

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Answer 1

Explanation:

2.7 m/s^2 = 64 m/s 0 m/s/t

2.7(t) = 64

t = 64 ÷ 2,7

t = 23.703

or => 23,7

S = 0×(23.7) + 1/2[2,7 × (23,7)²]

S= 1/2(2.7 × 561.7)

S = 758.295 meters

In conclusion:

the speed of the plane is 758.295 meters

Answer 2

758.295 meters

Explanation:

If for any reason my answer is wrong, feel free to correct me.

As per your question,

The airplanes accelerate uniformly at 2.7 meters per second^2

And they must reach a ground velocity of 64 m/s.

Therefore

S(Displacement) = u(initial velocity) x time + 1/2(acceleration x time^2)

Initial Velocity = 0 m/s(airplane is at rest)
Acceleration is 2.7m/s^2
Time = ?

Acceleration = Final Velocity - Initial Velocity / Time(t)

2.7 m/s^2 = 64 m/s - 0 m/s / t

2.7(t) = 64
t = 64/2.7

t = 23.703703... rounded to 23.7

S = 0(23.7) + 1/2[2.7 x (23.7)^2]

S = 1/2(2.7 x 561.7) 561.69 is the original answer rounded to 561.7

S = 758.295 meters

Final Answer - An airport would require a runway of minimum length of 758.295 meters to accommodate aircraft of the respective specifications.