Question

1. I. CH₂=CH-CH₂

II, CH₂-C
CH₂
III.
CH₂
1Ct₂
Which of the following orders is correct for the stability of these radicals?
a) I > II > III
c) I > III > II
b) III >II>I
d) III >1>II

Answer 1

Option A: I > II > III.

Step-by-step explanation:

The stability of radicals depends on the number of bonds and electrons they have. In general, radicals with more bonds and electrons are more stable than those with fewer bonds and electrons.

In this case, the correct order of stability of the radicals is option (a) I > II > III.

I. CH₂-C• is the most stable radical because it has the most number of bonds and electrons, it has 4 sigma bonds and 4 pi electrons.

II. CH₂• is less stable than I because it has 3 sigma bonds and 2 pi electrons.

III. CH• is the least stable of the three radicals because it has only 2 sigma bonds and 1 pi electron.

Option III >II>I, or III >1>II, is not correct because it doesn't match with the stability order of the given radicals.