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A hot air ballon is hovering 104 meters above the ground and begins to assend at a rate of 11 meters per second. Let

y be the height of the balloon in meters x seconds after it begins to assend.

Write an equation in slope-intercept form that models the height of the balloon.

How high is the balloon after 19 seconds?

User Boo
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Answer: The height of the balloon in meters x seconds after it begins to ascend can be represented by the equation y = mx + b, where m is the slope (the rate of change in height) and b is the y-intercept (the initial height of the balloon).

Given that the balloon is hovering 104 meters above the ground and begins to ascend at a rate of 11 meters per second, we can substitute these values into the equation:

y = 11x + 104

This equation is in slope-intercept form, the slope (m) is 11 and the y-intercept (b) is 104. This equation represents the height of the balloon in meters x seconds after it begins to ascend.

To find the height of the balloon after 19 seconds, we can substitute x = 19 into the equation:

y = 11(19) + 104 = 209 meters

So the hot air balloon is 209 meters high after 19 seconds.

Explanation:

User Jozef Chocholacek
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