Question

HELP FAST
How to find the complex zeroes of
`x^2-6x+13`

Answer 1

There are few possible ways to find the complex zeros

You can find the complex zeros by using quadratic formula

`x^2-6x+13=0`

`=(-\left(-6\right)\pm √(\left(-6\right)^2-4\cdot \:1\cdot \:13))/(2\cdot \:1)`

`x_(1,\:2)=(-\left(-6\right)\pm \:4i)/(2\cdot \:1)`

`x_1=(-\left(-6\right)+4i)/(2\cdot \:1),\:x_2=(-\left(-6\right)-4i)/(2\cdot \:1)`

`x=3+2i,\:x=3-2i`