168k views
2 votes
The difference of twice a number and 9 is at least -25.

1 Answer

6 votes

Answer:

x≥-8

Explanation:

Because we don't know the first number mentioned, we can name it as x

Since the problem starts off with "twice a number" so we mark it as 2x and then it states to take the difference of that number and 9. So the new problem we have is 2x-9=?. Now, the answer that we have is at least -25, so the answer is no longer an equal sign, but a greater-than or equal-to sign. Making our new equation 2x-9≥-25. Now we can act as if its a normal equation, adding 9 to both sides making it 2x≥-16, divide both sides by 2 to get x≥-8.

An extra step to ensure our answer is more than or equal to -8 is by plugging in -8 AND another number that is more than -8. 2(-8)-9=? which we would find that ? is -25. A number that is greater than -8 could be -1, which we would test by doing 2(-1)-9=?. ? would be equal to -11 so we know that our final answer of x≥-8 is correct.

User Mehta
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories