Question

A bullet of mass mb=11.9gr is being fired from a stationary gun of mass mg=2.1kg. If the velocity of the bullet is vb=235.1 m/s, what would be the recoil velocity of gun, vg, in m/s?

Answer 1

Answer:given that-

Bullet mass= 11.9gr

gun mass= 2.1

Velocity of bullets= 235.1m/s

A/q,

satisfied-

law of conservation of momentum

pf=pi

(Mass of gun+ mass of bullets)reserve velocity= mass of bullets ×velo of bullets

=>( 2100+11.9)vr=11.9×235.1

=>(2111.9 )vr=2797.69

=>vr=297.69/2111.9

vr=1.32m/