To find the values of A, B, and C for the quadratic equation y = x² + 4x - 2, we substituted x-values -2, 0, and 2 into the equation, which yielded y-values of -6, -2, and 10 respectively To complete the table of values for the equation y = x² + 4x - 2, we need to choose values for x, substitute them into the equation, and then solve for y. The equation is quadratic, not linear, since it includes an x² term.
Let's choose the values -2, 0, and 2 for x to find the corresponding y values. For x = -2, we have:
y = (-2)² + 4(-2) - 2
y = 4 - 8 - 2
y = -6
Next, for x = 0:
y = (0)² + 4(0) - 2
y = -2
Finally, for x = 2:
y = (2)² + 4(2) - 2
y = 4 + 8 - 2
y = 10
Therefore, the values that replace A, B, and C are -6, -2, and 10, respectively.