Question

a car is travelling at 18.1m/s with a constant acceleration of 3.7m/s^2. the car is attempting to pass a truck which is moving at a constant velocity of 29.7m/s. how far in meters must the car travel until it matches the trucks velocity

Answer 1

Explanation:

?

The car must travel a distance of 130.7 meters. This can be determined by using the equation for distance travelled with a constant acceleration:

Distance = Initial Velocity x Time + (1/2) x Acceleration x Time^2

In this case, the initial velocity is 18.1m/s, the acceleration is 3.7m/s^2, and the final velocity is 29.7m/s. We can set the final velocity equal to the initial velocity and solve for time:

29.7m/s = 18.1m/s + 3.7m/s^2 x Time

Time = 5.4 seconds

We can then plug this value for time into the equation for distance:

Distance = 18.1m/s x 5.4s + (1/2) x 3.7m/s^2 x 5.4s^2

Distance = 130.7 meters