Question

Calculate the Keq for the following reaction based on the concentrations provided 2 NO(g) + O2(g) = 2 NO2(g)[NO]= 0.50M [O2] = 0.75M [NO2] = 0.25M

Answer 1

Keq = 0.333 M⁻¹

Step-by-step explanation

Chemical equation of the reaction:

2NO(g) + O₂(g) ⇄ 2NO₂(g)

Given concentrations:

[NO] = 0.50M, [O2] = 0.75M, and [NO2] = 0.25M.

The formula for Keq for the reaction is

`\text{Keq }=\frac{\lbrack NO_2\rbrack^2}{\lbrack NO_{}\rbrack^2\lbrack O_2\rbrack}^{}`

Therefore,

`\text{Keq }=(0.25^2)/(0.5^2*0.75)=\frac{0.0625}{0.25*\text{0}.75}=(0.0625)/(0.1875)=0.333M^(-1)`