Question

Solve for x: 4•2^5 = 21 А. 0.42ОВ. 0.48ооооОс. 0.31OD D. 0.08

Answer 1

B. 0.48

Step-by-step explanation:

Given the below;

`4\cdot2^(5x)=21`

We'll follow the below steps to solve for x;

Step 1: Divide both sides of the equation by 4;

`\begin{gathered} (4\cdot2^(5x))/(4)=(21)/(4) \\ 2^(5x)=(21)/(4) \end{gathered}`

Step 2: Take the natural log of both sides of the equation;

`\begin{gathered} \ln (2^(5x))=\ln ((21)/(4)) \\ 5x\ln 2=\ln ((21)/(4)) \end{gathered}`

Step 3: Divide both sides by 5 ln 2;

`\begin{gathered} x=(\ln ((21)/(4)))/(5\ln 2) \\ x=0.48 \end{gathered}`