Answer: a. To find the age of a shark that is 200 centimeters long, we can set the function equal to 200 and solve for t:
L = 266 - 219e^(-0.05t)
200 = 266 - 219e^(-0.05t)
Solving this equation for t, we get t ≈ 2.11 years.
b. To find the length of a shark that is twice as old as the shark in part (a), we can substitute 2.11*2= 4.22 for t into the function:
L = 266 - 219e^(-0.05(4.22))
This will give us the length of the shark that is twice as old as the shark in part (a) in centimeters.