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Log9 (8-2x) = log9(-3x+2)

User Jeswang
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1 Answer

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Answer: X=-6

Step-by-step explanation: Since both logarithms have a base of 9, we can simply get rid of them. We could also do 9^(log9(8-2x))=9^(log9(-3x+2)). This would eliminate the logarithms.

Now we are just left with a simple algebraic equation: 8-2x=-3x+2.

We add 3x on both sides to get 8+x=2. We subtract 8 on both sides to get x=-6. There is no need to create a domain for the values of x since this is not an inequality problem.

User Tsvetan Ovedenski
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