Question

Find the equation of the line passing through the given point and perpendicular to the given line​

Answer 1

5x + y = 34

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given

x - 5y = 8 ( subtract x from both sides )

- 5y = - x + 8 ( divide through by - 5 )

y =
`(1)/(5)` x -
`(8)/(5)` ← in slope- intercept form

with slope m =
`(1)/(5)`

given a line with slope m then the slope of a line perpendicular to it is

`m_(perpendicular)` = -
`(1)/(m)` = -
`(1)/((1)/(5) )` = - 5 , then

y = - 5x + c ← is the partial equation

to find c substitute (5, 9 ) into the partial equation

9 = - 25 + c ⇒ c = 9 + 25 = 34

y = - 5x + 34 ← equation of perpendicular line in slope- intercept form

add 5x to both sides

5x + y = 34 ← equation in standard form