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In the last minute rush to assemble the demonstration, your teacher spills the lead chloride all over their sandwich and is left with 57.2 grams in the bottle. How much potassium iodide should be weighed out to convert all of the lead chloride to product?

User Jor
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In order to convert all of the 57.2 grams of lead chloride to product, you would need to weigh out 91.5 grams of potassium iodide. According to the balanced equation, PbCl2 + 2KI -> PbI2 + 2KCl, for every 1 mole of PbCl2, 2 moles of KI are required.
User MadaManu
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