Question

Please somebody please help ​

Answer 1

`{\Large \begin{array}{llll} y=ab^x \end{array}} \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} x=1\\ y=27 \end{cases}\implies 27=ab^1\implies 27=ab \\\\[-0.35em] ~\dotfill`

`\begin{cases} x=2\\ y=243 \end{cases}\implies 243=ab^2\implies 243=abb\implies \cfrac{243}{ab}=b \\\\\\ \stackrel{\textit{substituting from the 1st equation}}{\cfrac{243}{27}=b\implies \boxed{9=b}} \\\\\\ 27=ab\implies \cfrac{27}{b}=a\implies \cfrac{27}{9}=a\implies \boxed{3=a}~\hfill {\Large \begin{array}{llll} y=3(9)^x \end{array}}`