Question

A car, initially at rest, accelerates at 8.7 m/s2 for a total of 9.7 s. How far did it go in this time?

Answer 1

We can use the next formula

`d=ut+(at^2)/(2)`

where d is the distance, u is the initial velocity, a is the acceleration, t is the time.

In this case

u=0 m/s

a=8.7 m/s^2

t=9.7 s

we susbtitute

`d=(0)(9.7)+((8.7)(9.7)^2)/(2)=409.3m`

ANSWER

The distance is 409.3 m