Question

A rectangle is 6 times as long as it is wide. The perimeter is 50 cm. Find the dimensions of the rectangle. Round to the nearest tenth if necessary.

Answer 1

we have the following:

`\begin{gathered} p=2\cdot l+2\cdot w \\ l=6\cdot w \\ p=50 \end{gathered}`

replacing:

`\begin{gathered} 50=2\cdot(6\cdot w)+2\cdot w \\ 50=12w+2w \\ w=(50)/(14) \\ w=3.57 \end{gathered}`

now,

`\begin{gathered} l=6\cdot3.57 \\ l=42.86 \end{gathered}`

therefore, the wide is 3.57 cm and the length is 42.86 cm