Question

Dividing Polynomials Long Division Step by step(9x^2-6x-6)÷(3x-1)

Answer 1

You have the next division of polynomials:

`(9x^2-6x-6)/(3x-1)`

To make it you:

1. Write as follow:

2. You take the first term of the numarator by the first term of the denominator:

`(9x^2)/(3x)`

you get:

`3x`

You write the result on the green line.

3. Multiply the 3x by the denominator:

`3x(3x-1)=9x^2-3x`

4. Substract the result of multiplication above from the numerator, as follow: as the operation is a subtraction the symbol between the terms turn into a +

Then you lower the last term of the numerator next to the result of the substraction: to get a new polynomial (in this case -3x-6)

5. Repeat steps 2, 3 and :

`(-3x)/(3x)=-1`
`-1(3x-1)=-3x+1`