Question

F(x)=Sin2x ,x0=pi:3

f(x)=3x-x^2 ,x0=-1

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Answer 1

For the first function, F(pi:3) = sin(2 * pi:3) = sin(6 * pi / 3) = sin(2 * pi) = 0.

For the second function, f(-1) = 3 * -1 - (-1)^2 = -3 + 1 = -2.

Explanation:

It looks like you are trying to find the value of two different functions at specific points.

For the first function, F(x) = sin(2x) and x0 = pi:3, we want to find the value of F(x) when x = pi:3. Plugging this value into the function gives us F(pi:3) = sin(2 * pi:3) = sin(6 * pi / 3) = sin(2 * pi) = 0.

For the second function, f(x) = 3x - x^2 and x0 = -1, we want to find the value of f(x) when x = -1. Plugging this value into the function gives us f(-1) = 3 * -1 - (-1)^2 = -3 + 1 = -2.