Question

I need to find the weight of the cast iron shape

Answer 1

Density of iron:

`0.2607(lb)/(in^3)`

Then the weight of the cast iron shape is given by 0.2607*V, whe V is its volume.

The volume of the cast iron shape is given by its base area multiplied by its height. Since its base has the form of an equilateral triangle with side length of 4 in, its area is . Then we have:

`\begin{gathered} V=4\sqrt[]{3}\cdot6=24\sqrt[]{3}\approx41.6in^3 \\ \text{Therefore, the weight is:} \\ 0.2607\cdot24\sqrt[]{3}=10.8\text{ }lb \end{gathered}`