Answer:
See below for solution
When I post this I lose the formatting but you should be able to figure it out
Explanation:
Part a
p q ∼ ( p ∨ ∼ q ) → ∼ p
------------------------------------------------------------
True True True
True False True
False True True
False False True
Part b
p q r p → ( q → r )
-----------------------------------------------------------------
True True True True
True True False False
True False True True
True False False True
False True True True
False True False True
False False True True
False False False True
Part c
p q r ( p → q ) → r
-----------------------------------------------------------
True True True True
True True False False
True False True True
True False False True
False True True True
False True False False
False False True True
False False False False
Part d
p q (p → q)→(p ∧ q)
---------------------------------------------------
True True True
True False True
False True False
False False False