Question

Hello may i please recieve some assistance on this question? It will be greatly appreciated.

Answer 1

`k\text{ = 10}`

Step-by-step explanation:

For (x+2) to be a factor of the polynomial, if we set x+2 to 0, then substitute the value for x, we would get 0

Mathematically, we have it that:

`\begin{gathered} x+2\text{ = 0} \\ x\text{ = -2} \end{gathered}`

We can now proceed to substitute -2 into the polynomial as follows:

`\begin{gathered} (-2)^3-6(-2_{})^2-11(-2)+k\text{ = 0} \\ -8-24+22+k\text{ = 0} \\ -32+22+k\text{ = 0} \\ k\text{ = 32-22} \\ k\text{ = 10} \end{gathered}`